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ICSE-VIII-Mathematics

07: Percent and Percentage Class 8 Maths

with Solutions - page 2

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  • #5-i
    80 to 100
    Ans : Original number = 80
    New number = 100,
    Change = (100 - 80) = 20
    ∴ Percentage change = (increase)
    = 20/80 × 100
    = 25%
  • #5-ii
    100 to 80
    Ans : Original number = 100
    New number = 80
    Change (100 - 80) = 20
    ∴ Percentage change(decrease) = 20/100 × 100
    = 20%
  • #5-iii
    6.25 to 7.50
    Ans : Original number = 6.25,
    New number = 7.50
    Change (Increase) = (7.50 - 6.25) = 1.25
    ∴ Increase = 1.25/6.25 × 100
    = 20%
  • Qstn #6
    An auctioneer charges 8% for selling a house. If a house is sold for Rs. 2,30,500; find the charges of the auctioneer.
    Ans : Selling price of the house = Rs 2,30,500
    Rate of charges of the auctioneer = 8% of selling price
    ∴ Charges of the auctioneer =8% of 2,30,500
    = 8/100 × 2,30,500
    = Rs. 18,440
  • Qstn #7
    Out of 800 oranges, 50 are rotten. Find the percentage of good oranges.
    Ans : Total number of oranges = 800
    Number of good oranges = 800 - 50
    = 750
    Percentage of good oranges = 750/850 × 100
    = 750/8 = 375/4 = 93 ¾%
  • Qstn #8
    A cistern contains 5 thousand litres of water. If 6% water is leaked. Find how many litres of water are left in the cistern.
    Ans : Water in the cistern = 5000 Liters
    Quantity of water leaked = 6/100 × 5000
    = 300 litres
    Quantity of water left in the cistern = (5000 - 300) = 4700 litres
  • Qstn #9
    A man spends 87% of his salary. If he saves Rs. 325; find his salary.
    Ans : Let salary = Rs x
    ∴ Expenditure = 87/100 of x
    = Rs 87x/100
    Saving = Rs. 325
    ∴ x - 87x/100 = 325
    ⇒ (100x - 87x)/100 = 325⇒ 13x/100 = 325
    ⇒ x = (325 × 100)13⇒ x = 32500/13
    ⇒ x = 2500
    ∴ Salary = Rs. 2500
  • #10
  • #10-i
    A number 3.625 is wrongly read as 3.265; find the percentage error.
    Ans : Correct number = 3.625
    Number wrongly read as = 3.265
    Error = 3.625 - 3.265
    = 0.360
    % Error = 0.360/3.625 × 100
    = 360/3625 × 100= 36000/3625
    = 9.93%
  • #10-ii
    A number 5.78 × 103 is wrongly written as 5.87 × 103; find the percentage error
    Ans : Correct number = 5.78 × 103
    Number wrongly written as = 5.87 × 103
    Error = 5.87 × 103 - 5.78 × 103
    = 0.09 × 103
    % Error = (0.09 × 103)/(5.78 × 103) × 100
    = 0.09/5.78 × 100
    = 9/578 × 100
    = 900/578%
    = 1.56%
  • Qstn #11
    In an election between two candidates, one candidate secured 58% of the votes polled and won the election by 18, 336 votes. Find the total number of votes polled and the votes secured by each candidate.
    Ans : Since, winning candidate secured 58% of the votes polled.
    ∴ Losing candidate secured = (100 - 58)% of the votes polled
    = 42% of the votes polled
    Difference of votes = 58 - 42
    = 16% of the votes polled
    We are given :
    16% of votes polled = 18, 336
    ⇒ 16/100 of votes polled = 18, 336
    ⇒ Votes polled = 18,336 × 100/16
    ⇒ Votes polled = 18,33,600/16
    ⇒ Votes Polled = 1, 14,600
    ∴ Votes secured by winning candidate = 58/100 × 1,14, 600
    = 66,468
    Votes secured by losing candidate = 42/100 × 1,14,600
    = 48,132
    Votes polled = 1,14,600
    Votes secured by winning candidate = 66,468
    Votes secured by losing candidate = 48,132
  • Qstn #12
    In an election between two candidates, one candidate secured 47% of votes polled and lost the election by 12, 366 votes. Find the total votes polled and die votes secured by the winning candidate.
    Ans : Since, the losing candidate secured 47% of the votes polled
    Winning candidate secures votes = (100 - 47)% of the votes polled
    = 53% of the votes polled
    Difference of votes = 53 - 47
    = 6% of the votes polled
    We are given:
    6% of the votes polled = 12,366
    ⇒ 6/100 of the votes polled = 12,366
    ⇒ Votes polled = 12,366 × 100/6
    ⇒ 1236600/6
    ⇒ 2,06,100
    Votes secured by winning candidate = 53/100 × 2,06,100 = 1,09233
    ∴ Votes polled = 2,06,100
    Votes secured by winning candidate = 1,09,233
  • Qstn #13
    The cost of a scooter depreciates every year by 15% of its value at the beginning of the year. If the present cost of the scooter is
    ₹ 8,000; find its cost:
    Ans : Present cost of scooter = Rs. 8000
    The cost of scooter depreciates by 15% every year
  • #13-i
    after one year
    Ans : Cost of scooter after one year = (100 - 15)/100 × 8000
    = 85/100 × 8000
    = Rs 6800
  • #13-ii
    after 2 years
    Ans : Cost of scooter after 2 years = (100 - 15)/100 × 6800
    = 85/100 × 6800
    = Rs. 5780
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