ICSE-VIII-Mathematics

07: Percent and Percentage Class 8 Maths

with Solutions -

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    Section : A
  • #1-i
    55% of 160 + 24% of 50 - 36% of 150
    Ans : 55% of 160 + 24% of 50 - 36% of 150
    = (55 × 160)/100 + (24 × 50)/100 - (36 × 150)/100
    = 11 × 8 + 12 - 18 × 3 = 88 + 12 - 54 = 46
  • #1-ii
    9.3% of 500 - 4.8% of 250 - 2.5% of 240
    Ans : 9.3 % of 500 - 4.8% of 250 - 2.5% of 240
    = (9.3 × 500)/100 - (4.8 × 250)/100 - (2.5 × 240)/100
    9.3 × 5 - 1.2 × 10 - 0.5 × 12
    = 46.5 - 12 - 6
    = 46. 5 - 8
    = 28.5
  • #2
  • #2-i
    A number is increased from 125 to 150; find the percentage increase.
    Ans : Original value = 125, New value = 150
    Increase = (150 - 125) = 25
    Increase % = 25/125 × 100 = 20%
  • #2-ii
    A number is decreased from 125 to 100; find the percentage decrease.
    Ans : Original number = 125, New value = 100,
    Decrease = (125 - 100) = 25
    Decrease % = 25/125 × 100 = 200%
  • #3-i
    45 is what percent of 54?
    Ans : Let 45 = x percent of 54 = (54 × x)/100
    ⇒ x = (45 × 100)/54 = (5 × 100)/6
    = 250/3 = 83 1/3%
    ∴ Reqd. percentage = 83 1/3%
  • #3-ii
    2.7 is what percent of 18?
    Ans : Let 2.7 = x percent of 18 = (18 × x)/100
    ∴ x = (2.7 × 100)/18 = 270/18 = 30/2 = 15
    ∴ Reqd. percentage = 15%
  • #4
  • #4-i
    252 is 35% of a certain number, find the number.
    Ans : Let the number be x
    By the given condition,
    252 = (x × 35)/100 = (x × 7)/20
    ∴ x = (252 × 20)/7 = 36 × 20 = 720
    Hence reqd. number = 720
  • #4-ii
    If 14% of a number is 315; find the number.
    Ans : Let the number be x
    By the given condition,
    315 = (x × 14)/100
    ∴ x = (315 × 100)/14
    = (45 × 100)/2
    = 45 × 50
    = 2250
    Hence, reqd. number = 2250
  • Qstn #5
    Find the percentage change, when a number is changed from :