ICSE-VIII-Mathematics
06: Sets Class 8 Maths
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- #Section : A
- #1-iA1 = {x : 2x + 3 = 11}Ans : A1 = {x : 2x + 3 = 11}
∴ 2x + 3 = 11
⇒ 2x = 11 - 3
⇒ 2x = 8
⇒ x = 8/2 ⇒ x = 4
∴ Given set in roster (Tabular) form is
A1 = {4}
- #1-iiA2 = {x : x2 - 4x - 5 = 0}Ans : A2 = {x : x2 - 4x - 5 = 0}
∴ x2 - 4x - 5 = 0
⇒ x2 - 5x + x - 5 = 0
⇒ x(x - 5) + 1(x - 5) =0
⇒ (x - 5)(x + 1) = 0
∴ Either x - 5 = 0 or x + 1 = 0
⇒ x = 5 ⇒ x = -1
∴ Given set in roster (Tabular) form is A2 = {5, -1}
- #1-iiiA3 = {x : x ∈ Z, -3 ≤ x < 4}Ans : A3 = {x : x ∈ Z, -3 ≤ x < 4}
∵ -3 ≤ x < 4
∴ x = -3, -2, -1, 0, 1, 2, 3
∴ Given set in roster (Tabular) form is
A3 = {-3, -2, -1, 0, 1, 2, 3}
- #1-ivA4 = {x : x is a two digit number and sum of digits of x is 7}Ans : A4 = {x : x is a two digit number and sum of digits of x is 7}
∵ x is a two digit number and sum of digits of x is 7
∴ x = 16, 25, 34, 43, 52, 61, 70
∴ Given set in roster (Tabular) form is
A4 = {16, 25, 34, 43, 52, 61, 70}
- #1-vA5 = {x : x = 4n, n ∈ W and n < 4}Ans : A5 = {x : x = 4n, n ∈ W and n < 4}
∵ x = 4n
∴ When n = 0, x = 4 × 0
⇒ x = 0
When n = 1, x = 4 × 1
⇒ x = 4
When n = 2, x = 4 × 2
⇒ x = 8
When n = 3, x = 4 × 3
⇒ x = 12
∴ Given set in roster (Tabular) form is
A5 = {0, 4, 8, 12}
- #1-viA6 = {x : x = n/(n + 2) ; n ∈ N and n > 5}Ans : A6 = {x : x = n/(n + 2); n ∈ N & n > 5}
∵ x = n/(n + 2)
∴ When n = 6, x = 6/(6 + 2)
⇒ x = 6/8⇒ x = ¾
When n = 7, x = 7/(7 + 2)⇒ x = 7/9
When n = 8, x = 8/(8 + 2)⇒ x = 8/10
⇒ x = 4/5
When n = 9, x = 9/(9 + 2)⇒ x = 9/11
∴ Given set in roster (Tabular) form is
A6 = {3/4, 7/9, 4/5, 9/11,...}
- #2-iB1 = {6, 9, 2, 15, ...}Ans : B1 = {6, 9, 12, 15, ....}
= {x : x = 3n + 3; n ∈ N}
- #2-iiB2 = {11, 13, 17, 19 }Ans : B2 = {11, 13, 17, 19}
= {x : x is a prime number between 10 and 20}
- #2-iiiB3 = (1/3, 3/5, 5/7, 7/9, 9/11,...}Ans : B3 = {1/3, 3/5, 5/7, 7/9, 9/11, ...}
= {x : x = n/(n + 2), where n is an odd natural number}
- #2-ivB4 = {8, 27, 64, 125, 216}Ans : B4 = {8, 27, 64, 125, 216}
= {x : x = n3; n ∈ N and 2 ≤ n ≤ 6}
- #2-vB5 = {-5, -4, -3, -2, -1}Ans : B5 = {-5, -4, -3, -2, -1}
= {x : x ∈ Z, -5 ≤ x ≤ -1}