CBSE-XI-Physics
47: The Special Theory of Relativity
- #1The magnitude of linear momentum of a particle moving at a relativistic speed v is proportional to
(a) v
(b) 1 - v2/c2
(c)
1-v2/c2
(d) none of thesedigAnsr: dAns : (d) none of these
Linear momentum of a particle moving at a relativistic speed v is given by
`` p=\frac{{m}_{o}v}{\sqrt{1-{\displaystyle \frac{{v}^{2}}{{c}^{2}}}}}``
Here, m​o is the rest mass of the particle.
So, linear momentum is proportional to `` \frac{v}{\sqrt{1-{\displaystyle \frac{{v}^{2}}{{c}^{2}}}}}``.
Hence, none of the above options is correct.
Page No 457: