Total number of nucleotide sequences of DNA that codes for a hormone is 1530. The
proportion of different bases in the sequence is found to be Adenine = 34%, Guanine
= 19%, Cytosine = 23%, Thymine = 19%.
Applying Chargaff’s rule, what conclusion can be drawn?
A. It is a double stranded circular DNA.
B. It is a single stranded DNA.
C. It is a double stranded linear DNA.
D. It is a single stranded DNA coiled on Histones.

A stretch of an euchromatin has 200 nucleosomes. How many bp will there be in the
stretch and what would be the length of the typical euchromatin?
A. 20,000 bp and 13,000 x10-9 m
B. 10,000 bp and 10,000 x10-9 m
C. 40,000 bp and 13,600 x10-9 m
D. 40,000 bp and 13,900 x10-9 m

Observe structures A and B given below. Which of the following statements are
correct?

A. A is having 2'-OH group which makes it less reactive and structurally stable,
whereas B is having 2'-H group which makes it more reactive and unstable.
B. A is having 2'-OH group which makes it more reactive and structurally unstable,
whereas B is having 2'-H group which makes it less reactive and
structurally stable.
C. A and B both have -OH groups which make it more reactive and structurally
stable.
D. A and B both are having -OH groups which make it less reactive and structurally
stable
12

If Meselson and Stahl's experiment is continued for sixth generations in bacteria, the
ratio of Heavy strands 15N/15N :Hybrid15N/14N : light 14N/14N containing DNA in the sixth
generation would be
A. 1:1:1
B. 0:1:7
C. 0:1:15
D. 0:1:31

Two important RNA processing events lead to specialized end sequences in most
human mRNAs: (i) at the 5’ end, and (ii) at the 3’ end. At the 5’ end
the most distinctive specialized end nucleotide, (iii) is added and a sequence of
about 200 (iv) is added to the 3’ end.
A. (i) Initiator codon (ii) Promotor (iii) Terminator codon (iv) Release factors
B. (i). Promotor (ii) Elongation (iii) Regulation (iv) Termination.
C. (i) Capping (ii) Polyadenylation (iii) mGppp (iv) Poly(A).
D. (i) Repressor (ii) Co repressor (iii) Operon (iv) sRelease factors

What are minisatellites?
A. 10-40 bp sized small sequences within the genes
B. Short coding repetitive region on the eukaryotic genome
C. Short non-coding repetitive sequence forming large portion of eukaryotic genome
D. Regions of coding strands of the DNA

There was a mix-up at the hospital after a fire accident in the nursery division. Which
of these children belong to the parents?

A. All of the children
B. Children 2, 3 & 6
C. Children 1 & 3
D. Children 2 & 4

The peak observed in Subject 1 and 2 is due to
A. estrogen
B. progesterone
C. luteinizing hormone
D. follicle stimulating hormone

Subject 2 has higher level of hormone B, which is
A. estrogen
B. progesterone
C. luteinizing hormone
D. follicle stimulating hormone

If the peak of Hormone A does not appear in the study for Subject 1, which of
the following statement is true?
A. Peak of Hormone B will be observed at a higher point in the graph
B. Peak of Hormone B will be observed at a point lower than what is given in the
graph
C. There will be no observed data for Hormone B
D. The graph for Hormone B will be a sharp rise followed by a plateau

Which structure in the ovary will remain functional in subject 2?
A. Corpus Luteum
B. Tertiary follicle
C. Graafian follicle
D. Primary follicle
14

For subject 2 it is observed that the peak for hormone B has reached the plateau
stage. After approximately how much time will the curve for hormone B descend?
A. 28 days
B. 42 days
C. 180 days
D. 280 days

Which of the following statements is true about the subjects?
A. Subject 1 is pregnant
B. Subject 2 is pregnant
C. Both subject 1 and 2 are pregnant
D. Both subject 1 and 2 are not pregnant

The gene that controls the ABO blood group system in human beings has three alleles
- IA, IB and i. A child has blood group O. His father has blood group A and mother has
blood group B. Genotypes of other off springs can be:
i. IBIB
ii. IAi
iii. IBi
iv. IAIB
v. ii
A. i, ii, iii, v
B. ii, iii ,iv, v
C. iii, iv, v
D. iv, iii, i