Previous Year Paper year:2015 : ICSE-X-Physics

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ICSE-X-Physics

Previous Year Paper year:2015

with Solutions - page 2

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#1-e-ii
In a beam balance when the beam is balanced in a horizontal position, it is in
______ equilibrium.
Ans : Static equilibrium.

#2

#2-a [2]
How is work done by a force measured when the force:

#2-a-i
is in the direction of displacement?
Ans : Work done by a force when the force is in the direction of displacement = Force x Displacement of the point of application of the force in the direction of force.

#2-a-ii
is in an angle to the direction of displacement?
Ans : Work done by a force when the force is at an angle [θ ] to the direction of displacement = Force x component of displacement in the direction of force = Force x d cos θ
[d is the displacement of the body at the angle θ to the direction of force]

#2-b [2]
State the energy in the following while in use:
Ans : Energy changes :

#2-b-i
Burning of a candle.
Ans : Burning of a candle: Chemical energy to light energy.

#2-b-ii
A steam engine.
Ans : Steam engine: Chemical energy of coal first changes to heat energy of steam and then heat energy charges into mechanical energy.

#2-c [2]

#2-c-i
A scissor is a _________ multiplier.
Ans : A scissor is a speed multiplier.

#2-c-ii
``\pu{1 kWh}`` = ________ J.
Ans : 1 kWh = 3.6 x 10⁶ J.

#2-d [2]
Explain the motion of a planet around the Sun in a circular path.
Ans : A planet moves around the sun in a circular path for which the gravitational force of attraction on the planet by the sun provides the necessary centripetal force. This centripetal force is always directed towards the centre of the sun at each point of its path which is responsible for circular motion of planet.

#2-e [2]
Rajan exerts a force of ``\pu{150 N}`` in pulling a cart at a constant speed of ``\pu{10 m//s}``.
Calculate the power exerted.
Ans : Given : Force = 150 N, Speed = 10 m/s.
Power = Force x Speed
= 150 x 10
= 1500 Watt.

#3

#3-a [2]