ICSE-X-Mathematics

Previous Year Paper year:2012

with Solutions - page 2

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  • #3-b [3]
    Evaluate without using trigonometric tables:
    $$\cos^2 26° + \cos^2 64° sin 26° + \frac{tan36°}{cot54°}$$
    Ans : ``cos^2 \ 26° + cos \ 64°.sin \ 26° + \frac{tan \ 36°}{cot \ 54°}``
    ``= cos^2 \ 26° + cos \ (90° - 26°).sin \ 26° + \frac{tan \ (90° - 54°)}{cot \ 54°} ``
    ``= cos^2 \ 26° + sin^2 \ 26° + \frac{cot \ 54°}{cot \ 54°} ``
    = 2
  • #3-c [4]
    Marks obtained by 40 students in a short assessment is given below, where a and b
    are two missing data.
    Marks 5 6 7 8 9
    Number of Students 6 a 16 13 b

    If the mean of the distribution is 7.2, find a and b.
    Ans : Given, the total number of students = 40
    Therefore 6 + a+ 16+ 13+ b = 40
    ``\Rightarrow a + b = 5 . . . (i)``
    Given ``mean (\overline{x}) = \frac {\Sigma fx}{\Sigma f} = 7.2 ``
    Therefore ``7.2 = \frac{5 \times 6 + 6 \times a +7 \times 16 +8 \times 13 +9 \times b}{40} ``
    246 + 6a + 9 b = 288
    6a + 9 b = 42
    2a + 3b = 14 . . . (ii)
    Solving (i) and (ii) we get a = 1 and b = 4
  • #4
  • #4-a [3]
    Kiran deposited Rs. 200 per month for 36 months in a bank.s recurring deposit
    account. If the bank pays interest at the rate of 11% per annum, find the
    amount she gets on maturity.
    Ans : ``P = Rs. \ 200, \ no \ of \ months = 36, \ r = 11\%``
    Maturity ``\ Value = P \times n + P \times \frac{n(n+1)}{2 \times 12} \times \frac{r}{100}``
    ``=200 \times 36 +200 \times \frac{36(36+1)}{2 \times 12} \times \frac{11}{100} = Rs. 8421 ``
  • #4-b
    Two coins are tossed once. Find the probability of getting
    Ans : Let Heads . H and Tails . T
    If two coins are tossed once, then the total number of possibilities would be as shown: Sample Space (S) = {HH, HT, TH, TT}
    n (S) = 4 (i.e. there are 4 possible outcomes)
  • #4-b-i [3]
    2 heads (ii) at least 1 tail.
    Ans : Event: getting two heads ``= {HH} \Rightarrow n(E) = 1 ``
    Hence the probability ``P(E) = \frac{n(E)}{n(S)} = \frac{1}{4} = 0.25 ``
  • #4-c
    Using graph paper and taking 1 cm = 1 unit along both x-axis and y-axis.
    Ans : (i) Please refer to the graph shown below
  • #4-c-i
    Plot the points A(-4, 4) and B(2, 2).
  • #4-c-ii
    Reflect A and B in the origin to get the images A. and B. respectively.
    Ans : Please refer to the graph shown below
  • #4-c-iii
    Write down the co-ordinates of A. and B..
    Ans : Reflection of ``A \ and \ B`` in the origin are ``A'(4, -4) \ and \ B'(-2, -2)`` respectively.
  • #4-c-iv
    Give the geometrical name for the figure ABA.B..
    Ans : Name of the geometrical figure in the graph show is Rhombus
  • #4-c-v [4]
    Draw and name its lines of symmetry.
    Ans : Two lines of symmetry: Both diagonal ``AA' \ and \ BB'``
  • # [40]
    Section : B
    Attempt any four questions from this Section
  • #5
  • #5-a [3]
    In the given figure, AB is the diameter of a circle with centre O. ∠BCD = 130°. Find:
    Ans :