ICSE-X-Chemistry
Previous Year Paper year:2018
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- #1-i-ivDry hydrogen chloride gas can be collected by ________ displacement of
air. (downward / upward)Ans : Dry hydrogen chloride gas can be collected by the upward displacement
of air.
- #1-i-vThe most common ore of iron is _________. (calamine / haematite)Ans : The most common ore of iron is haematite .
- #1-i-viThe salt prepared by the method of direct combination is ________.
(iron (II) chloride/ iron (III) chloride)
Ans : The salt prepared by the method of direct combination is iron (III)
chloride.
- # [40]Section : IIAttempt any four questions from this Section
- #2
- #2-a [3]
- #2-a-iWhat do you understand by a lone pair of electrons?Ans : A lone pair of electrons: A pair of electrons which is not shared with any
other atom is known as a lone pair of electrons. It is provided to the other
atom for the formation of a coordinate bond.
- #2-a-iiDraw the electron dot diagram of Hydronium ion. (H=1; O=8)Ans : Electron dot diagram of hydronium ion:
;
- #2-b [3]In Period 3 of the Periodic table, element B is placed to the left of element A.
On the basis of this information, choose the correct word from the brackets
to complete the following statements:
- #2-b-iThe element B would have (lower /higher) metallic character than A.Ans : The clement B would have lower metallic character than A.
- #2-b-iiThe element A would probably have (lesser / higher) electron affinity
than B.Ans : The element A would probably have higher electron affinity than B.
- #2-b-iiiThe element A would have (greater /smaller) atomic size than B.Ans : The element A would have smaller atomic size than B.
- #2-c [4]Copy and complete the following table which refers to the conversion of ions to neutral particles.
Conversion Ionic Equation Oxidation / Reduction Chloride ion to chlorine molecule (i) …………………… (ii) …………………… Lead (II) ion to lead (iii) …………………… (iv) …………………… Ans :Conversion Ionic Equation Oxidation/Reduction (i) Chloride ion to chlorine molecule (i) $$\ce{Cl- - e- -> Cl }$$
$$\ce{ Cl + Cl -> Cl2 }$$(i) Oxidation (ii) Lead (II) ion to lead (ii) $$\ce{Pb^{2+} + 2e- ->
Pb }$$(ii) Reduction
- #3
- #3-a [3]